For this simple example, doing it without the chain rule was a loteasier. because in the chain of computations. Find the derivative of \(f(x) = (3x + 1)^5\). \end{equation} Thus, \begin{equation} \frac{dv}{d s}=\frac{-12t+8}{-6t^2+8t+1}. Solution. When trying to decide if the chain rule makes sense for a particular problem, pay attention to functions that have something more complicated than the usual x. Comments are currently disabled. Therefore, the rule for differentiating a composite function is often called the chain rule. For example, if a composite function f (x) is defined as The composition or “chain” rule tells us how to ﬁnd the derivative of a composition of functions like f(g(x)). Using the chain rule and the product rule we determine, \begin{equation} g'(x)=2x f\left(\frac{x}{x-1}\right)+x^2f’\left(\frac{x}{x-1}\right)\frac{d}{dx}\left(\frac{x}{x-1}\right)\end{equation} \begin{equation} = 2x f\left(\frac{x}{x-1}\right)+x^2f’\left(\frac{x}{x-1}\right)\left(\frac{-1}{(x-1)^2}\right). This looks complicated, so let’s break it down. By the chain rule $$ g'(x)=f'(3x-1)\frac{d}{dx}(3x-1)=3f'(3x-1)=\frac{3}{(3x-1)^2+1}. Video Transcript. This is called a tree diagram for the chain rule for functions of one variable and it provides a way to remember the formula (Figure \(\PageIndex{1}\)). This section gives plenty of examples of the use of the chain rule as well as an easily understandable proof of the chain rule. Chain rule for events Two events. Differentiation Using the Chain Rule SOLUTION 1 : Differentiate. However, we can get a better feel for it using some intuition and a couple of examples. Theorem. Let u = x2 so that y = cosu. The general power rule states that this derivative is n times the function raised to the (n-1)th power … Suppose that the functions $f$, $g$, and their derivatives with respect to $x$ have the following values at $x=0$ and $x=1.$ \begin{equation} \begin{array}{c|cccc} x & f(x) & g(x) & f'(x) & g'(x) \\ \hline 0 & 1 & 1 & 5 & 1/3 \\ 1 & 3 & -4 & -1/3 & -8/3 \end{array} \end{equation} Find the derivatives with respect to $x$ of the following combinations at a given value of $x,$ $(1) \quad \displaystyle 5 f(x)-g(x), x=1$ $(2) \quad \displaystyle f(x)g^3(x), x=0$ $(3) \quad \displaystyle \frac{f(x)}{g(x)+1}, x=1$$(4) \quad \displaystyle f(g(x)), x=0$ $(5) \quad \displaystyle g(f(x)), x=0$ $(6) \quad \displaystyle \left(x^{11}+f(x)\right)^{-2}, x=1$$(7) \quad \displaystyle f(x+g(x)), x=0$$(8) \quad \displaystyle f(x g(x)), x=0$$(9) \quad \displaystyle f^3(x)g(x), x=0$. The arguments of the functions are linked (chained) so that the value of an internal function is the argument for the following external function. But I wanted to show you some more complex examples that involve these rules. If g(-1)=2, g'(-1)=3, and f'(2)=-4, what is the value of h'(-1) ? However, that is not always the case. Then, to compute the derivative of y with respect to David Smith (Dave) has a B.S. For problems 1 – 27 differentiate the given function. You can think of \(g\) as the “outside function” and \(h\) as the “inside function”. David is the founder and CEO of Dave4Math. For each of the following functions, write the function ${y=f(x)}$ in the form $y=f(u)$ and $u=g(x)$, then find $\frac{dy}{dx}.$$(1) \quad \displaystyle y=\left(\frac{x^2}{8}+x-\frac{1}{x}\right)^4$$(2) \quad \displaystyle y=\sec (\tan x)$$(3) \quad \displaystyle y=5 \cos ^{-4}x$$(4) \quad \displaystyle y=e^{5-7x}$ $(5) \quad \displaystyle y=\sqrt{2x-x^2}$$(6) \quad \displaystyle y=e^x \sqrt{2x-x^2}$, Exercise. Also, read Differentiation method here at BYJU’S. To prove the chain rule let us go back to basics. This resource is … This section gives plenty of examples of the use of the chain rule as well as an easily understandable proof of the chain rule. And, in the nextexample, the only way to obtain the answer is to use the chain rule. Using the chain rule, \begin{equation} \frac{d}{d x}f'[f(x)] =f” [ f(x)] f'(x) \end{equation} which is the second derivative evaluated at the function multiplied by the first derivative; while, \begin{equation} \frac{d}{d x}f [f'(x)]=f'[f'(x)]f”(x) \end{equation} is the first derivative evaluated at the first derivative multiplied by the second derivative. You know by the power rule, that the derivative of \(x^5\) is \(5x^4\). $$ If $g(x)=f(3x-1),$ what is $g'(x)?$ Also, if $ h(x)=f\left(\frac{1}{x}\right),$ what is $h'(x)?$. Also learn what situations the chain rule can be used in to make your calculus work easier. Exercise. Determine if the following statement is true or false. Since it was actually not just an \(x\), you will have to multiply by the derivative of the \(3x+1\). If x + 3 = u then the outer function becomes f = u 2. A few are somewhat challenging. The chain rule does not appear in any of Leonhard Euler's analysis books, even though they were written over a hundred years after Leibniz's discovery. (a) Find the tangent to the curve $y=2 \tan (\pi x/4)$ at $x=1.$ (b) What is the smallest value the slope of the curve can ever have on the interval $-2

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